# BANKING & IT : SI & CI, DATE 10/05/2020

1
1278 # Banking & IT (SI & CI)

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#### Banking & IT (SI & CI)

Question 1 of 25.

1. Rs. 10000
2. 6000
3. 5000
4. 2000

### 5000

If Diff. between SI & CI for 2 years is Rs. x, then Principal = x (100/r)2 P = 50 x (100x100)/(10x10) → P = 5000.

Question 2 of 25.

1. 4000
2. 5200
3. 4250
4. 5000

### 5000

If Diff. between SI & CI for 2 years is Rs. x, Principal = x (100/r)2 P = 162 x (100x100)/(18x18) → P = 5000.

Question 3 of 25.

1. 5
2. 6
3. 7
4. 8

### 8 %

SI = Rs. 200 = Rs. 100 + Rs. 100
CI = Rs. 208 = Rs. 100 + Rs. 108 (In first year SI & CI are equal.)
Therefore, Rs.8 Gap is because of the interest of 1st year interest.
Rs. 8 is interest on Rs. 100, R= (8x100)/(100x1) % ,R = 8%

Question 4 of 25.

1. 1200
2. 2500
3. 750
4. 1250

### 2500

Apply: Principal = x (100/r)2 where x is the difference in CI & SI for 2 years. ∴ P = 25(100/10)2 = 2500.

Question 5 of 25.

1. 16 %
2. 20/3 %
3. 12 %
4. 10 %

### 20/3 %

SI for 3 years = 150 → SI for 1 years = 75
∴ CI for 1 year = 75. So CI for 2nd year = 80 and SI for 2nd year = 75. Difference = 5 ∴ Rate of interest = (5/75) x 100 = 20/3 %.

Question 6 of 25.

1. 11 5/7%
2. 10%
3. 20%
4. 13 5/7%

### 11 5/7%

Let, the capital of Sahil = 6. ∴ Capital of Chaya = 7 = 11 5/7%

Question 7 of 25.

1. 12000
2. 21000
3. 37000
4. 63000

### 12000

Let ‘x’ be the sum that Khan borrows. Then the total simple interest that Khan pays is the sum of the interests. We can write from the formula of the simple interest, [x×6×2]/100 + [x×9×3]/100 + [x×14×4]/100 = Rs. 11400.

Therefore we can write, 95x/100 = 11400 or x = Rs. 12000 and hence the correct option is A) Rs. 12000.

Question 8 of 25.

1. 600
2. 666
3. 780
4. 800

### 800

Let the sum be Rs. a. Then we can write: [{x×10×7}/{100×2}] – [{x×12×5}/{100×2}] = 40.. This can be written as: 7x/20 – 3x/10 = 4o. Therefore we have x = Rs. 800

Hence the sum is Rs. 800 and the correct option is D) Rs. 800.

Question 9 of 25.

1. 12000
2. 11000
3. 15000
4. 14000

### 15000

the principal = Rs. [{100×5400}/{12×3}] = Rs. 15000. Thus the correct option is D) Rs. 15000.

Question 10 of 25.

1. 2
2. 3
3. 4
4. 5

### 3%

Simple interest = 27250 – 25000 = 2250

Time = 3 years.

SI = PTR / 100 → R = SI * 100 / PT

R = 2250 * 100 / 25000 * 3 → R = 3%.

Question 11 of 25.

1. 10%
2. 10.25%
3. 10.5%

### 10.25%

S.I. for first 6 months

= Rs. [100 × 10 × 1  / 100 × 2] = Rs.5

S.I. for last 6 months = Rs. [105 × 10 × 1  / 100 × 2] = Rs.5.25

So, amount at the end of 1 year = Rs. (100 + 5 + 5.25) = Rs.110.25

So, effective rate = (110.25 ⎯ 100) = 10.25%

Question 12 of 25.

1. 6.8%
2. 7.1%
3. 8%
4. 9%

### 8 %

A = P [1 + (R / 100)]n

→ 5832 = 5000 [1 + (R / 100)]2

→ [1 + (R / 100)]2 = 5832 / 5000

→ [1 + (R / 100)]2 = 11664 / 10000

→ [1 + (R / 100)] = 108 / 100

→ R / 100 = 8 / 100

→ R = 8 %

Thus, the required rate of interest per annum in 8 %

Question 13 of 25.

1. 400, 600
2. 800, 1200
3. 300, 500
4. 700, 900

### 400,600

→ Sum lent at 8 % = 1000 – P

Now, according to the question,

SI for 5 % + SI for 8 % = 62

→ (P x 5 x 1 / 100) + ((1000 – P) x 8 x 1 / 100) =62

→ 5 P + 8 (1000 – P) = 6200

→ 5 P + 8000 – 8 P = 6200

→ 3 P = 1800

→ P = 600

Therefore, sum lent at 5 % = P = Rs. 600

Sum lent at 8 % = 1000 – P = Rs. 400

Question 14 of 25.

### A sum of Rs. 1000 is to be divided among two brothers such that if the interest being compounded annually is 5 % per annum, then the money with the first brother after 4 years is equal to the money with the second brother after 6 years.

1. 425 and 498
2. 400 and 489
3. 500 and 575
4. 524.38 and 475.62

### 524.38 and 475.62

→ Money with second brother = Rs. 1000 – P

Now, according to the question,

P [1 + (5 / 100)]4 = (1000 – P) [1 + (5 / 100)]6

→P (1.05)4 = (1000 – P) (1.05)6

→ 0.9070 P = 1000 – P

→ 1.9070 P = 1000

→ P = 524.38

Therefore, share of first brother = Rs. 524.38

Share of second brother = Rs. 475.62

Question 15 of 25.

1. Rs. 120
2. Rs. 121
3. Rs. 122
4. Rs. 123

### Rs. 121

Amount
 = Rs. 1600 x 1 + 5 2 + 1600 x 1 + 5  2 x 100 2 x 100

 = Rs. 1600 x 41 x 41 + 1600 x 41 40 40 40

 = Rs. 1600 x 41 41 + 1  40 40

 = Rs. 1600 x 41 x 81 40 x 40
= Rs. 3321. C.I. = Rs. (3321 - 3200) = Rs. 121

Question 16 of 25.

1. 625
2. 630
3. 640
4. 650

### 625

Let the sum be Rs. x. Then,

 C.I. = x 1 + 4 2 - x = 676 x - x = 51 x. 100 625 625

 S.I. = x x 4 x 2 = 2x . 100 25 51x - 2x = 1 625 25 x = 625.

Question 17 of 25.

### An Informal Gathering occurs when a group of people get together in a casual, relaxed manner. Which situation below is the best example of an Informal Gathering?

1. A debating club meets on the first Sunday morning of every month.
2. After finding out about his salary raise, Jay and a few colleagues go out for a quick dinner after work.
3. Meena sends out 10 invitations for a bachelorette party she is giving for her elder sister.
Question 18 of 25.

### Which word is the odd man out?

1. hate
2. fondness
3. liking
4. attatchment
Question 19 of 25.

### Melt : Liquid :: Freeze :

1. Ice
2. solid
3. condense
4. push
Question 20 of 25.

### Look at this series: 80, 10, 70, 15, 60, … What number should come next?

1. 20
2. 25
3. 30
4. 50
Question 21 of 25.

### Which word does NOT belong with the others?

1. inch
2. ounce
3. centimeter
4. yard
Question 22 of 25.

### When the Principal entered the class, a student………. on the blackboard.

1. Wrote
2. was writing
3. writes
4. is writing
Question 23 of 25.

### Select Correct Word

1. Agressive
2. Agrressive
3. Aggressive
4. Aggresive
Question 24 of 25.

### My grand father will come here —– a week.

1. with
2. before
3. at
4. within
Question 25 of 25.

### The work was completed —– sunset.

1. for
2. in
3. at

#### Next question 1 of 25

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